If 16 2⁄3 % of a number is added with
itself then result becomes 4249.Find
the original No.?

(a) 3642 
(b) 4132 
(c) 4124 
(d) 3142
16 2⁄3 % = 50⁄3 × 1⁄100 = 2⁄6 1 by 6 hai means 6 ka 16 2⁄3 % ,1 hai 6 | +16 2⁄3 % [6+ 16 2⁄3 % of 6 =6+1=7] 7 7=4269 so 6 {original no}= 4269/7 × 6 =3642
If 30% of a No. is added with itself then result becomes 2639. Find the original No.?

(a) 2010
(b) 2030
(c) 2020 
(d) 2040
    
original no ko 100 man lo 100 me 30% add to 130 100 |+30% 130 130=2639 so 100= {2639⁄130} ×100 = 2030

    
If 80 is added in a number then No. becomes 120% of itself. Find the number.?
20%=80 100%=400 confirmation = 480 ,400 ka kitna % hai = 480⁄400 ×100 =120 100% |+80 means 20%=80 120
If 20% of a number is 50, what is 87.5% of that number?
  
20%=50 87.5%= 50⁄20 ×87.5 = 218.75
If 20% of 320 is x less than 40% of 460, find x?

126
122
120
118
    
20% of 320 + x = 40% of 460 64+x=184 x=120
If x is 8⁄5 % of y then what percent of x is y?
    
x = 8⁄5 % of y x= 8⁄5 × 1⁄100 of y x= ⁸ʸ⁄500 y , x ka kitna percent hai? ( 10th me 500 me se 400 paye to kitna %) 400 ... 500 ka kitna % hai ⁴⁰⁰/₅₀₀ ×100 =80% yx ×100 { comapre x se ho rha to x niche} y/ [8y⁄500] × 100 500y⁄8y × 100 6250%
20 letres of a mixture contains 20 % alcohol and the rest water.If 4 leter water mixed in it .The percentage of alcohol in new mixture will he:

a) 33⅓%
b) 16⅔%
c) 25%
d) 12½%
    
 A man bought an old typewriter for 1200 and spend 200 on its repair.He sold it for 1680.His profit percentage 
 
 a) 20
 b) 10
 c) 8
 d) 16
    
A ,B se 25% adhik hai 

means..... ¼ adik hai means 4 me 1 adhik hai 
adikh.......{4+1}/4
Km...........{4-1}/4


A,B se 10% adhik hai .......⅒ adhik hai 

A={10+1}/10
    
If A's income is 40 % less then that of B's .How much percent B income is mote than that of A's?

a) 40
b) 60
c) 66.66%
d) 33.33%

    
Lets be income is 100 A income --- 40% km mtlb 60 Kitna % adhik hai to phle kitna adhik hai ye niklenge 100-60=40 adhik hai ⁴⁰⁄₆₀ × 100 =66.66% { niche 60 q= jisce compare hota hai o niche rakha jata}
If Nita's salary is 25 % more than Papiya salary,then the percentage by which Papaiya is less than Nita's salary is 

a) 15%
b) 20%
c) 25%
d) 32%
    
Lets papiya salary =100 Nita salary 25% adhik to ....125 kitna percent km hai to phle kitna km hai ye niklenge 125-100=25 25/125 ×100 =20% { 125 niche q= Nita se compare kar rhe to o niche }
Two number are respectively 20% and 50% of a third number. What percent is the first number of the second number.

a) 10
b) 20
c) 30
d) 40
    
Let third number is 100 |--20 ||---50 20/50 ×100=40 Jo pucha o upr jisce compare o niche
Two number are respectively 20% and 50% more then that of a third number.
a)  What percent is the first number of the second number.

b) By  what percentage is the second number greater than the first number?

c) By what percentage is the first number less  than the second number?

d) If we increase 1st number by 10% then the resultant is how much percent of third number.
        100 ,120 ,130,132
        
e) If we increase 1st number by 10% then the resultant is how much percent of second number after decreasing second number by 33.33%.
   
    
Let third number =100 |---20 % more than third number = 20% of 100 +100=120 ||--- 50% more=150
A number is first increased by 12% and then decreased by 12%. The change in number is:  
1.44% increase 
12% increase
Same 
1.44% decrease 
    
Three fifths of a number is 30 more than 50 percent of that number. What is the 80% of that number? 

a) 240
b) 60
c) 300
d) 340

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    

    






A reduction of 10% in the price of sugar enables a housewife to buy 6.2 kg more for Rs. 1116  .The reduced price per kg is

a) 16
b) 17
c) 18
d) 19
    
A reduction of 20% in the price of rice enables a person to buy 3.5 kg more for Rs. 77. Then the original price per kg is

a) 4
b) 4.5
c) 5
d) 5.5
    
A reduction of 21% in the price of wheat enables a person to buy 10.5 kg more for Rs. 100. What is the reduced price per kg?

a) 1
b) 2
c) 1.5
d) 2.5
    
A reduction of 10% in the price of sugar enables housewife to buy 6.2 kg more for Rs. 279. Find and reduced price per kilogram.

a) 4
b) 4.5
c) 5
d) 5.5
    
A reduction of 25% in the price of rice enables a person to buy 100 kg more rice for Rs. 6000. The reduced price per kg of rice is

a) 15
b) 20
c) 25
d) 30
    
A reduction of 10% in the price of rice enables a person to obtain 22 kg more for Rs. 250. What is the original price of rice per kg?

a) 7
b) 28
c) 1.26
d) 1.4
A reduction of 10% in the price of rice enables a shopkeeper to obtain 25 kg more for Rs. 2250. The original price per kg was

(a) Rs.20
(b) Rs.15
(c) Rs.10
(d) Rs.25
A reduction of 20% in the price of rice enables a person to purchase 10 kg more in Rs.600. Find the price of rice per kg before and after reduction of price.

Rs. 25 and Rs. 20
Rs. 15 and Rs. 12
Rs. 30 and Rs. 24 
Rs. 10 and Rs. 8 
    
A reduction of 20% in the price of rice enables a person to purchase 10 kg more in Rs. 600. Calculation: Let the price per kg was Rs. 100x and after 20% reduction new price becomes Rs. 80x According to question, New quantity rice – old quantity rice = 10 kg ⇒ 600/80x – 600/100x = 10 ⇒ 120/80x = 10 ⇒ x = 3/20 Original price = 100x = Rs. (100 × 3/20) = Rs. 15 per kg New price = 80x = Rs. (80 × 3/20) = Rs. 12 per kg ∴ Original price and the new price are Rs. 15/kg and Rs. 12/kg respectively.
If price of an apple is reduced by 30 percent ,it enable the customer to buy 5 more apples for 140. Find the reduced rate of the apple

a) 8.4
b) 8
c) 12
d) 12.5
The price of an item is reduced by 20%. As a result, customers can get 2 kg more of it for ₹360. Find the original price (in ₹) per kg of the item.

a) 3.5
b) 4.5
c) 36
d) 45
The price of an item is reduced by 20%. As a result, customers can get 2 kg more of it for ₹360 Calculation: 20% = 1/5 Let the actual price be 5x So, after reduction it will be 4x According to the question, (360/4x) - (360/5x) = 2 ⇒ (90/x) - (72/x) = 2 ⇒ [(90 - 72)/x] = 2 ⇒ 18 = 2x ⇒ x = 9 So, actual price = 5 × 9 = 45 ∴ The original price (in ₹) per kg of the item is 45.
A reduction of 20% in the price of rice enabes a customer to purchase 12.5 kg more for ₹ 800. The original price of rice (per kg) is

a) 8
b) 16
c) 12.8
d) 12
A reduction of 20% in the price of sugar enabes Ram to purchase 45 kg more for₹ 900, The original price of sugar (per kg) after reduction, is






Price of rice increased from 3 per kg to "4 per kg but there is no change in expenditure. Find effect on consumption of rice?

(a) 50% increase
(b) 25% decrease
(c) 25% increase
(d) 50% decrease
The price of bread is increased by 25%. To maintain the budget, Katrina reduces the consumption of this bread by 20%. The increase in expenditure due to this bread is:

a) 1%
b) 0%
c) 2%
d) 3%
In an election between A and B, B secured 16,200 votes and defeated A by 8% of the total votes. If there are no invalid votes, what is the difference in votes between A and B
In an election contested by two parties, party A secured 16 percent of the total votes more than party B. If party B got 25200 votes and there are no invalid votes, by how many votes did party B lose the election?

(a) 9600
(b) 1800
(O) 5400
(d) 6400
At an election between two candidates 95 votes were declared invalid. The winning secures 65% of the valid votes and win by 615 votes. Find the total number of votes polled ?
In an election between two candidates, the winning candidate has got 70% of the votes polled and has won by 15400 votes. What is the number of votes polled for losing candidate?

Percentage of votes won by winning candidate = 70% Percentage of votes obtained by losing candidate = 30% Concept used: Difference between the two = votes by which winning candidate won Calculation: 40% = 15400 1% = 385 Then, votes got by losing candidate = 30% = 11550 ∴ The votes polled for losing party are 11550
In an election between two candidates, 10% of the voters did not cast their vote. 10 % of the votes polled were found invalid. The successful candidates got 54% of the valid votes and won by a majority of 1620 votes. Find the number of votes enrolled on the voter's list.
In an election between two candidates, 75% of the voters cast their votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of enrolled voters.


A) 9261
B) 2600
C) 16800
D) 26800
In an election between two candidates, one got 55% of the total valid votes. 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was....

a) 2700
b) 2900
c) 3000
d) 3200
In an election between two candidates, the winning candidate has got 70% of the votes polled and has won by 15400 votes. What is the number of votes polled for losing candidate?

a) 38500
b) 11550
c) 13550
d) 26950
Percentage of votes won by winning candidate = 70% Percentage of votes obtained by losing candidate = 30% Concept used: Difference between the two = votes by which winning candidate won Calculation: 40% = 15400 1% = 385 Then, votes got by losing candidate = 30% = 11550 ∴ The votes polled for losing party are 11550
In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate.

A) 357000
B) 280000
C) 387500
D) 355700

In an election only two candidates contested, 20 percent of the voters did not caste their vote and 120 votes were declared invalid. The winner got 200 votes more than his opponent which he secured was 41 percent of the total votes on the voter list. Percentage of the votes of the defeated candidate out of the total votes cast is:

45 percent
36 percent
38 percent 
37.5 percent
Let the total votes be 80%x Valid votes = 80%x - 120 Winner got = 41%x Looser got = 41%x - 200 According to the question, 80%x - 120 = 41%x + 41%x - 200 ⇒ 80%x - 120 = 82%x - 20 ⇒ -120 + 200 = 82%x - 80%x ⇒ 80 = 2x% ⇒ x = (80 × 100)/2 = 4000 Total vote = (80 × 4000)/100 = 3200 Looser got = 41%x - 200 = (41/100 × 4000) - 200 = 1640 - 200 = 1440 Required% = (1440/3200) × 100 = 45% ∴ Required percentage is 45%.