Find the smallest number which when divided by 12, 13, 18 and 26 , the remaining 9 came in each case.

481
475
479
477
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Mtlb in sbse divide ho jana chahiye aur 9 remainder ana chahiye

sbse divide ho jaye means LCM

remainder bhi bachna chahiye means lcm niklne ke bad add 


LCM ( 12,13,18,26) ===>468
............468 o smallest  number hai jo 12,13,18,26 se puri trh divide ho jata hai

but hume 9 remainder bhi chahiye to 9 add kr denge
468+9 ==>477 answer


Answer by short trick

Option ko hi update krke remainder ko gyb kr do 

means agr hum remainder ko option me se subtract kr de fir 12,13,18,26 se divide hone me kuch bhi remainder nhi bachega

481-9===>472
475-9===>464
479-9===>470
477-9===>468

aise jo new option aye o 12,13,18,26 se puri trh divisible honge


18 bhi hai isme means option me digit ka sum 9 hoga to wahi wala sahi hoga


472 ===> 4 + 7 + 2 = 13
464 ===> 4 + 6 + 4 = 14
470 ===> 4 + 7 + 0 = 11
477 ===> 4 + 7 + 7 = 18

Isme bs 18 hi 9 se divisible hai means option 4 sahi hai

Find the least multiple of 23, which when divided by 18,21 and 24 leaves the remainder 7, 10 and 13 respectively.

a) 3013
b) 3024
c) 3002
d) 3036
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The sum of two numbers is 36 and their H.C.F. and L.C.M. are 3 and 105 respectively. The sum of the reciprocals of two numbers is

²⁄₂₅

²⁄₃₅

⁴⁄₃₅

³⁄₂₅
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Let two numbers be m and n
 ∴ m + n = 36
We know, Product of two number =H.C.F x L.C.M
 
m × n = L.C.M X H.C.F = 3 X 105 = 315

Sum of reciprocals =
¹/ₙ  + ¹/ₘ =====>  ⁽ᵐ⁺ⁿ⁾／ₘₙ ==>  ³⁶/₃₁₅ =  ⁴⁄₃₅

Sum of two numbers is 384. HCF of the numbers is 48. The difference of the numbers is = ?

A. 100
B. 192
C. 288
D. 336
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Answer: Option C

Solution(By Examveda Team)
HCF = 48
Let number are 48x and 48y respectively
⇒48x+48y=384(x+y)=38448=8

So, possible pairs of co-prime number are (1, 7) (3, 5)
numbers are (48, 336) or (144, 240)
∴ difference between numbers is = 336 - 48
= 288 and 240 - 144 = 96
     

The HCF of two numbers, each having three digits, is 17 and their LCM is 714. The sum of the numbers will be:

A. 289
B. 391
C. 221
D. 731
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Answer: Option C

Let the numbers be 17x and 17y where x and y are co-prime.
LCM = 17xy
Now, 17xy = 714
Or, xy = 42 = 6 × 7
→x = 6 and y = 7
Or, x = 7 and y = 6
1st number = 17 × 6 = 102
2nd number = 17 × 7 = 119
Sum = 102 + 119 = 221
     

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Sum of HCF & LCM is 168 and difference is 120 . one number is 72 then other?
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